Ireland vs Tajikistan: Repetition rate in Grade 1 of lower secondary general education, both
Ireland
0.2%
in 2017
Tajikistan
0.2%
in 2016
Ireland rank
151st
Tajikistan rank
153rd
Repetition rate in Grade 1 of lower secondary general education, both over time
- Ireland
- Tajikistan
How they compare
Ireland currently reports 0.2% against 0.2% in Tajikistan, a difference of 0.0%.
That makes Ireland's figure about 1.1 times Tajikistan's.
The two have swapped places 1 time across 16 shared years of data; in 1998 it was Tajikistan ahead.
Ireland ranks 151st and Tajikistan ranks 153rd of 178 countries.
Across the 3 decades both report, Ireland averaged higher in 1 and Tajikistan in 2.
Head to head by decade
| Decade | Ireland | Tajikistan | Difference | Ahead |
|---|---|---|---|---|
| 1990s | 0.6% | 1.2% | 0.7% | Tajikistan |
| 2000s | 0.4% | 0.6% | 0.3% | Tajikistan |
| 2010s | 0.2% | 0.2% | 0.1% | Ireland |
Averages of every year both report within each decade.
Frequently asked questions
- Which has higher repetition rate in grade 1 of lower secondary general education, both, Ireland or Tajikistan?
- Ireland, at 0.2% against 0.2% in Tajikistan as of 2017.
- What is the difference in repetition rate in grade 1 of lower secondary general education, both between Ireland and Tajikistan?
- 0.0%, with Ireland ahead.
- How many years of comparable data are there for Ireland and Tajikistan?
- 16 years are reported by both, from 1998 to 2016.
- How do Ireland and Tajikistan rank globally for repetition rate in grade 1 of lower secondary general education, both?
- Ireland ranks 151st and Tajikistan ranks 153rd of 178 countries.
- Where does this data come from?
- UNESCO Institute for Statistics, published as Repetition rate in Grade 1 of lower secondary general education, both sexes (%). Statizoid refreshes it automatically from the source and publishes the full history for both places.
Individual pages
About this data
Number of repeaters in a given grade in a given school year, expressed as a percentage of enrolment in that grade the previous school year. Divide the number of repeaters in a given grade in school year t+1 by the number of pupils from the same cohort enrolled in the same grade in the previous school year t.